10-(1/x)-(9/x^2)=0

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Solution for 10-(1/x)-(9/x^2)=0 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

10-(1/x)-(9/(x^2)) = 0

10-x^-1-9*x^-2 = 0

t_1 = x^-1

10-9*t_1^2-1*t_1^1 = 0

10-9*t_1^2-t_1 = 0

DELTA = (-1)^2-(-9*4*10)

DELTA = 361

DELTA > 0

t_1 = (361^(1/2)+1)/(-9*2) or t_1 = (1-361^(1/2))/(-9*2)

t_1 = -10/9 or t_1 = 1

t_1 = -10/9

x^-1+10/9 = 0

1*x^-1 = -10/9 // : 1

x^-1 = -10/9

-1 < 0

1/(x^1) = -10/9 // * x^1

1 = -10/9*x^1 // : -10/9

-9/10 = x^1

x = -9/10

t_1 = 1

x^-1-1 = 0

1*x^-1 = 1 // : 1

x^-1 = 1

-1 < 0

1/(x^1) = 1 // * x^1

1 = 1*x^1 // : 1

1 = x^1

x = 1

x in { -9/10, 1 }

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